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10010132133 = 33336710711
BaseRepresentation
bin10010101001010011…
…00111111010100101
3221211121211101210120
421110221213322211
5131000043212013
64333143512153
7503026501461
oct112451477245
927747741716
1010010132133
114277505481
121b34458659
13c36b27211
146ad63d4a1
153d8c10123
hex254a67ea5

10010132133 has 4 divisors (see below), whose sum is σ = 13346842848. Its totient is φ = 6673421420.

The previous prime is 10010132129. The next prime is 10010132201. The reversal of 10010132133 is 33123101001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33123101001 = 311041033667.

It is a cyclic number.

It is not a de Polignac number, because 10010132133 - 22 = 10010132129 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10010132533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668355353 + ... + 1668355358.

It is an arithmetic number, because the mean of its divisors is an integer number (3336710712).

Almost surely, 210010132133 is an apocalyptic number.

It is an amenable number.

10010132133 is a deficient number, since it is larger than the sum of its proper divisors (3336710715).

10010132133 is an equidigital number, since it uses as much as digits as its factorization.

10010132133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3336710714.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10010132133 its reverse (33123101001), we get a palindrome (43133233134).

The spelling of 10010132133 in words is "ten billion, ten million, one hundred thirty-two thousand, one hundred thirty-three".

Divisors: 1 3 3336710711 10010132133