Base | Representation |
---|---|
bin | 1001000110101010111110… |
… | …0111010100110001110111 |
3 | 1022102222010110012012111001 |
4 | 2101222233213110301313 |
5 | 2303001412322334312 |
6 | 33142344233424131 |
7 | 2052133405056115 |
oct | 221525747246167 |
9 | 38388113165431 |
10 | 10010220121207 |
11 | 320a346324389 |
12 | 115806a56b047 |
13 | 577c62626617 |
14 | 2686d65d0ab5 |
15 | 1255c72d2057 |
hex | 91aaf9d4c77 |
10010220121207 has 2 divisors, whose sum is σ = 10010220121208. Its totient is φ = 10010220121206.
The previous prime is 10010220121199. The next prime is 10010220121351. The reversal of 10010220121207 is 70212102201001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10010220121207 - 23 = 10010220121199 is a prime.
It is a super-2 number, since 2×100102201212072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10010220121507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005110060603 + 5005110060604.
It is an arithmetic number, because the mean of its divisors is an integer number (5005110060604).
Almost surely, 210010220121207 is an apocalyptic number.
10010220121207 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010220121207 is an equidigital number, since it uses as much as digits as its factorization.
10010220121207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 10010220121207 its reverse (70212102201001), we get a palindrome (80222322322208).
The spelling of 10010220121207 in words is "ten trillion, ten billion, two hundred twenty million, one hundred twenty-one thousand, two hundred seven".
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