Base | Representation |
---|---|
bin | 1001000110101011011011… |
… | …1100001111010000010001 |
3 | 1022102222110000111100000021 |
4 | 2101222312330033100101 |
5 | 2303002140304402423 |
6 | 33142404344223441 |
7 | 2052136426642666 |
oct | 221526674172021 |
9 | 38388400440007 |
10 | 10010343044113 |
11 | 320a3a9752165 |
12 | 11580a376ab81 |
13 | 577c81c34a79 |
14 | 268708a6ba6d |
15 | 1255d2eb395d |
hex | 91ab6f0f411 |
10010343044113 has 8 divisors (see below), whose sum is σ = 10256161892256. Its totient is φ = 9764603440800.
The previous prime is 10010343043997. The next prime is 10010343044147. The reversal of 10010343044113 is 31144034301001.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10010343044113 - 213 = 10010343035921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10010343044153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19555423 + ... + 20060788.
It is an arithmetic number, because the mean of its divisors is an integer number (1282020236532).
Almost surely, 210010343044113 is an apocalyptic number.
It is an amenable number.
10010343044113 is a deficient number, since it is larger than the sum of its proper divisors (245818848143).
10010343044113 is an equidigital number, since it uses as much as digits as its factorization.
10010343044113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39622415.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 10010343044113 its reverse (31144034301001), we get a palindrome (41154377345114).
The spelling of 10010343044113 in words is "ten trillion, ten billion, three hundred forty-three million, forty-four thousand, one hundred thirteen".
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