Base | Representation |
---|---|
bin | 101110100111010101… |
… | …0110101101001010001 |
3 | 100120101102112012012022 |
4 | 1131032222311221101 |
5 | 3120003122203213 |
6 | 113553122141225 |
7 | 10142446546211 |
oct | 1351652655121 |
9 | 316342465168 |
10 | 100104100433 |
11 | 394aa178317 |
12 | 174987b1815 |
13 | 959425a72c |
14 | 4bb8bdc241 |
15 | 290d44e308 |
hex | 174eab5a51 |
100104100433 has 2 divisors, whose sum is σ = 100104100434. Its totient is φ = 100104100432.
The previous prime is 100104100429. The next prime is 100104100451. The reversal of 100104100433 is 334001401001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96666271744 + 3437828689 = 310912^2 + 58633^2 .
It is an emirp because it is prime and its reverse (334001401001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100104100433 - 22 = 100104100429 is a prime.
It is not a weakly prime, because it can be changed into another prime (100104100403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50052050216 + 50052050217.
It is an arithmetic number, because the mean of its divisors is an integer number (50052050217).
Almost surely, 2100104100433 is an apocalyptic number.
It is an amenable number.
100104100433 is a deficient number, since it is larger than the sum of its proper divisors (1).
100104100433 is an equidigital number, since it uses as much as digits as its factorization.
100104100433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 100104100433 its reverse (334001401001), we get a palindrome (434105501434).
The spelling of 100104100433 in words is "one hundred billion, one hundred four million, one hundred thousand, four hundred thirty-three".
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