100104113 has 4 divisors (see below), whose sum is σ = 100159488. Its totient is φ = 100048740.

The previous prime is 100104089. The next prime is 100104127. The reversal of 100104113 is 311401001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100104113 - 2¹⁶ = 100038577 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 100104094 and 100104103.

It is not an unprimeable number, because it can be changed into a prime (100104013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24881 + ... + 28622.

It is an arithmetic number, because the mean of its divisors is an integer number (25039872).

Almost surely, 2^100104113 is an apocalyptic number.

It is an amenable number.

100104113 is a deficient number, since it is larger than the sum of its proper divisors (55375).

100104113 is an equidigital number, since it uses as much as digits as its factorization.

100104113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55374.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 100104113 is about 10005.2042957653. The cubic root of 100104113 is about 464.3199107368.

Adding to 100104113 its reverse (311401001), we get a palindrome (411505114).

The spelling of 100104113 in words is "one hundred million, one hundred four thousand, one hundred thirteen".