10010434124113 has 4 divisors (see below), whose sum is σ = 10159843588720. Its totient is φ = 9861024659508.

The previous prime is 10010434124083. The next prime is 10010434124179. The reversal of 10010434124113 is 31142143401001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10010434124113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10010434124213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74704732203 + ... + 74704732336.

It is an arithmetic number, because the mean of its divisors is an integer number (2539960897180).

Almost surely, 2^{10010434124113} is an apocalyptic number.

It is an amenable number.

10010434124113 is a deficient number, since it is larger than the sum of its proper divisors (149409464607).

10010434124113 is an equidigital number, since it uses as much as digits as its factorization.

10010434124113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149409464606.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 10010434124113 its reverse (31142143401001), we get a palindrome (41152577525114).

The spelling of 10010434124113 in words is "ten trillion, ten billion, four hundred thirty-four million, one hundred twenty-four thousand, one hundred thirteen".