Base | Representation |
---|---|
bin | 10110110000110010101101… |
… | …100101011010001001010001 |
3 | 111010110102102201112120000102 |
4 | 112300302231211122021101 |
5 | 101110200300024444303 |
6 | 552525523110502145 |
7 | 30041465241542132 |
oct | 2660625545321121 |
9 | 433412381476012 |
10 | 100110009999953 |
11 | 29997464867408 |
12 | b289ba7964955 |
13 | 43b2444734685 |
14 | 1aa14c9479c89 |
15 | b891576e0288 |
hex | 5b0cad95a251 |
100110009999953 has 2 divisors, whose sum is σ = 100110009999954. Its totient is φ = 100110009999952.
The previous prime is 100110009999929. The next prime is 100110010000009. The reversal of 100110009999953 is 359999900011001.
It is an a-pointer prime, because the next prime (100110010000009) can be obtained adding 100110009999953 to its sum of digits (56).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86303969940049 + 13806040059904 = 9289993^2 + 3715648^2 .
It is a cyclic number.
It is not a de Polignac number, because 100110009999953 - 214 = 100110009983569 is a prime.
It is not a weakly prime, because it can be changed into another prime (100110009099953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055004999976 + 50055004999977.
It is an arithmetic number, because the mean of its divisors is an integer number (50055004999977).
Almost surely, 2100110009999953 is an apocalyptic number.
It is an amenable number.
100110009999953 is a deficient number, since it is larger than the sum of its proper divisors (1).
100110009999953 is an equidigital number, since it uses as much as digits as its factorization.
100110009999953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 885735, while the sum is 56.
The spelling of 100110009999953 in words is "one hundred trillion, one hundred ten billion, nine million, nine hundred ninety-nine thousand, nine hundred fifty-three".
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