Base | Representation |
---|---|
bin | 11101001000101100100… |
… | …01101010101101110011 |
3 | 10112201000110100121121202 |
4 | 32210112101222231303 |
5 | 112400223341011011 |
6 | 2043522143041415 |
7 | 132220135014443 |
oct | 16442621525563 |
9 | 3481013317552 |
10 | 1001101110131 |
11 | 356623529271 |
12 | 14202a8a026b |
13 | 735324478b5 |
14 | 3664c794123 |
15 | 1b09326b23b |
hex | e91646ab73 |
1001101110131 has 2 divisors, whose sum is σ = 1001101110132. Its totient is φ = 1001101110130.
The previous prime is 1001101110091. The next prime is 1001101110137. The reversal of 1001101110131 is 1310111011001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1001101110131 - 214 = 1001101093747 is a prime.
It is a super-2 number, since 2×10011011101312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1001101110137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500550555065 + 500550555066.
It is an arithmetic number, because the mean of its divisors is an integer number (500550555066).
Almost surely, 21001101110131 is an apocalyptic number.
1001101110131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001101110131 is an equidigital number, since it uses as much as digits as its factorization.
1001101110131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 1001101110131 its reverse (1310111011001), we get a palindrome (2311212121132).
The spelling of 1001101110131 in words is "one trillion, one billion, one hundred one million, one hundred ten thousand, one hundred thirty-one".
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