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1001101112131 is a prime number
BaseRepresentation
bin11101001000101100100…
…01101011001101000011
310112201000110100201100211
432210112101223031003
5112400223341042011
62043522143054551
7132220135023331
oct16442621531503
93481013321324
101001101112131
1135662352a81a
1214202a8a1457
1373532448793
143664c794b51
151b09326bb21
hexe91646b343

1001101112131 has 2 divisors, whose sum is σ = 1001101112132. Its totient is φ = 1001101112130.

The previous prime is 1001101112071. The next prime is 1001101112147. The reversal of 1001101112131 is 1312111011001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1001101112131 - 219 = 1001100587843 is a prime.

It is a super-3 number, since 3×10011011121313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1001101112171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500550556065 + 500550556066.

It is an arithmetic number, because the mean of its divisors is an integer number (500550556066).

Almost surely, 21001101112131 is an apocalyptic number.

1001101112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001101112131 is an equidigital number, since it uses as much as digits as its factorization.

1001101112131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 1001101112131 its reverse (1312111011001), we get a palindrome (2313212123132).

The spelling of 1001101112131 in words is "one trillion, one billion, one hundred one million, one hundred twelve thousand, one hundred thirty-one".