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100110113 = 739135467
BaseRepresentation
bin1011111011110…
…00111100100001
320222101010020222
411331320330201
5201112010423
613533412425
72323631135
oct575707441
9228333228
10100110113
1151567234
122963a115
131798196c
14d41d3c5
158bc73c8
hex5f78f21

100110113 has 4 divisors (see below), whose sum is σ = 100246320. Its totient is φ = 99973908.

The previous prime is 100110061. The next prime is 100110119. The reversal of 100110113 is 311011001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100110113 - 28 = 100109857 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100110113.

It is not an unprimeable number, because it can be changed into a prime (100110119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66995 + ... + 68472.

It is an arithmetic number, because the mean of its divisors is an integer number (25061580).

Almost surely, 2100110113 is an apocalyptic number.

It is an amenable number.

100110113 is a deficient number, since it is larger than the sum of its proper divisors (136207).

100110113 is an equidigital number, since it uses as much as digits as its factorization.

100110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 136206.

The product of its (nonzero) digits is 3, while the sum is 8.

The square root of 100110113 is about 10005.5041352248. The cubic root of 100110113 is about 464.3291872914.

Adding to 100110113 its reverse (311011001), we get a palindrome (411121114).

The spelling of 100110113 in words is "one hundred million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 739 135467 100110113