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1001101483 is a prime number
BaseRepresentation
bin111011101010111…
…001100010101011
32120202202020001201
4323222321202223
54022240221413
6243201025031
733544136134
oct7352714253
92522666051
101001101483
114741063a8
1223b325177
1312c534655
1496d56c8b
155cd4c9dd
hex3bab98ab

1001101483 has 2 divisors, whose sum is σ = 1001101484. Its totient is φ = 1001101482.

The previous prime is 1001101481. The next prime is 1001101511. The reversal of 1001101483 is 3841011001.

It is a weak prime.

It is an emirp because it is prime and its reverse (3841011001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1001101483 - 21 = 1001101481 is a prime.

Together with 1001101481, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1001101483.

It is not a weakly prime, because it can be changed into another prime (1001101481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500550741 + 500550742.

It is an arithmetic number, because the mean of its divisors is an integer number (500550742).

Almost surely, 21001101483 is an apocalyptic number.

1001101483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001101483 is an equidigital number, since it uses as much as digits as its factorization.

1001101483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

The square root of 1001101483 is about 31640.1877838928. The cubic root of 1001101483 is about 1000.3670262752.

Adding to 1001101483 its reverse (3841011001), we get a palindrome (4842112484).

The spelling of 1001101483 in words is "one billion, one million, one hundred one thousand, four hundred eighty-three".