1001104051 has 2 divisors, whose sum is σ = 1001104052. Its totient is φ = 1001104050.

The previous prime is 1001104019. The next prime is 1001104067. The reversal of 1001104051 is 1504011001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1001104051 - 2⁵ = 1001104019 is a prime.

It is a super-3 number, since 3×1001104051³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1001105051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500552025 + 500552026.

It is an arithmetic number, because the mean of its divisors is an integer number (500552026).

Almost surely, 2^1001104051 is an apocalyptic number.

1001104051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001104051 is an equidigital number, since it uses as much as digits as its factorization.

1001104051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20, while the sum is 13.

The square root of 1001104051 is about 31640.2283651683. The cubic root of 1001104051 is about 1000.3678816465.

Adding to 1001104051 its reverse (1504011001), we get a palindrome (2505115052).

The spelling of 1001104051 in words is "one billion, one million, one hundred four thousand, fifty-one".