Base | Representation |
---|---|
bin | 10010101001011010… |
… | …10100101110000011 |
3 | 221211200122200022122 |
4 | 21110231110232003 |
5 | 131000320231313 |
6 | 4333220354455 |
7 | 503040651353 |
oct | 112455245603 |
9 | 27750580278 |
10 | 10011102083 |
11 | 4278008194 |
12 | 1b34845a2b |
13 | c370a6858 |
14 | 6ad812b63 |
15 | 3d8d52708 |
hex | 254b54b83 |
10011102083 has 2 divisors, whose sum is σ = 10011102084. Its totient is φ = 10011102082.
The previous prime is 10011102041. The next prime is 10011102113. The reversal of 10011102083 is 38020111001.
It is a strong prime.
It is an emirp because it is prime and its reverse (38020111001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10011102083 - 26 = 10011102019 is a prime.
It is not a weakly prime, because it can be changed into another prime (10011104083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005551041 + 5005551042.
It is an arithmetic number, because the mean of its divisors is an integer number (5005551042).
Almost surely, 210011102083 is an apocalyptic number.
10011102083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011102083 is an equidigital number, since it uses as much as digits as its factorization.
10011102083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 10011102083 its reverse (38020111001), we get a palindrome (48031213084).
The spelling of 10011102083 in words is "ten billion, eleven million, one hundred two thousand, eighty-three".
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