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10011104341391 is a prime number
BaseRepresentation
bin1001000110101110010001…
…0100010110110110001111
31022110001102002000020112202
42101223210110112312033
52303010220202411031
633143012101352115
72052164332603406
oct221534424266617
938401362006482
1010011104341391
11320a75a45906a
12115827670863b
1357807388672a
1426877bc0063d
15125629c432cb
hex91ae4516d8f

10011104341391 has 2 divisors, whose sum is σ = 10011104341392. Its totient is φ = 10011104341390.

The previous prime is 10011104341309. The next prime is 10011104341463. The reversal of 10011104341391 is 19314340111001.

10011104341391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10011104341391 - 218 = 10011104079247 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011104343391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005552170695 + 5005552170696.

It is an arithmetic number, because the mean of its divisors is an integer number (5005552170696).

Almost surely, 210011104341391 is an apocalyptic number.

10011104341391 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011104341391 is an equidigital number, since it uses as much as digits as its factorization.

10011104341391 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 29.

Adding to 10011104341391 its reverse (19314340111001), we get a palindrome (29325444452392).

The spelling of 10011104341391 in words is "ten trillion, eleven billion, one hundred four million, three hundred forty-one thousand, three hundred ninety-one".