Base | Representation |
---|---|
bin | 10110110000110011101111… |
… | …110100010101101100011111 |
3 | 111010110112022011110212211101 |
4 | 112300303233310111230133 |
5 | 101110210034012211033 |
6 | 552530225243533531 |
7 | 30041534623635031 |
oct | 2660635764255437 |
9 | 433415264425741 |
10 | 100111121210143 |
11 | 2999798503903a |
12 | b28a257b2a2a7 |
13 | 43b2590a0b9b4 |
14 | 1aa1592c95c51 |
15 | b891c003c97d |
hex | 5b0cefd15b1f |
100111121210143 has 2 divisors, whose sum is σ = 100111121210144. Its totient is φ = 100111121210142.
The previous prime is 100111121210083. The next prime is 100111121210251. The reversal of 100111121210143 is 341012121111001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100111121210143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 100111121210143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100111121210843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055560605071 + 50055560605072.
It is an arithmetic number, because the mean of its divisors is an integer number (50055560605072).
Almost surely, 2100111121210143 is an apocalyptic number.
100111121210143 is a deficient number, since it is larger than the sum of its proper divisors (1).
100111121210143 is an equidigital number, since it uses as much as digits as its factorization.
100111121210143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 100111121210143 its reverse (341012121111001), we get a palindrome (441123242321144).
The spelling of 100111121210143 in words is "one hundred trillion, one hundred eleven billion, one hundred twenty-one million, two hundred ten thousand, one hundred forty-three".
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