Base | Representation |
---|---|
bin | 10110110000110011101111… |
… | …111000001010010101100101 |
3 | 111010110112022020100210101111 |
4 | 112300303233320022111211 |
5 | 101110210034241242242 |
6 | 552530225321225021 |
7 | 30041534635310335 |
oct | 2660635770122545 |
9 | 433415266323344 |
10 | 100111122212197 |
11 | 29997985662988 |
12 | b28a258332171 |
13 | 43b2590c9cb25 |
14 | 1aa15930770c5 |
15 | b891c0189817 |
hex | 5b0cefe0a565 |
100111122212197 has 2 divisors, whose sum is σ = 100111122212198. Its totient is φ = 100111122212196.
The previous prime is 100111122212081. The next prime is 100111122212207. The reversal of 100111122212197 is 791212221111001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100107508879876 + 3613332321 = 10005374^2 + 60111^2 .
It is a cyclic number.
It is not a de Polignac number, because 100111122212197 - 211 = 100111122210149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100111122222197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055561106098 + 50055561106099.
It is an arithmetic number, because the mean of its divisors is an integer number (50055561106099).
Almost surely, 2100111122212197 is an apocalyptic number.
It is an amenable number.
100111122212197 is a deficient number, since it is larger than the sum of its proper divisors (1).
100111122212197 is an equidigital number, since it uses as much as digits as its factorization.
100111122212197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 31.
Adding to 100111122212197 its reverse (791212221111001), we get a palindrome (891323343323198).
The spelling of 100111122212197 in words is "one hundred trillion, one hundred eleven billion, one hundred twenty-two million, two hundred twelve thousand, one hundred ninety-seven".
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