1001113001323 has 2 divisors, whose sum is σ = 1001113001324. Its totient is φ = 1001113001322.

The previous prime is 1001113001303. The next prime is 1001113001341. The reversal of 1001113001323 is 3231003111001.

It is a strong prime.

It is an emirp because it is prime and its reverse (3231003111001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1001113001323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1001113001297 and 1001113001306.

It is not a weakly prime, because it can be changed into another prime (1001113001303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500556500661 + 500556500662.

It is an arithmetic number, because the mean of its divisors is an integer number (500556500662).

Almost surely, 2^{1001113001323} is an apocalyptic number.

1001113001323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001113001323 is an equidigital number, since it uses as much as digits as its factorization.

1001113001323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1001113001323 its reverse (3231003111001), we get a palindrome (4232116112324).

The spelling of 1001113001323 in words is "one trillion, one billion, one hundred thirteen million, one thousand, three hundred twenty-three".