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10011134431 = 15359651809
BaseRepresentation
bin10010101001011010…
…11100100111011111
3221211200201022200201
421110231130213133
5131000322300211
64333221204331
7503041144564
oct112455344737
927750638621
1010011134431
11427802a521
121b348606a7
13c370b84ac
146ad82086b
153d8d5c0c1
hex254b5c9df

10011134431 has 4 divisors (see below), whose sum is σ = 10011801600. Its totient is φ = 10010467264.

The previous prime is 10011134423. The next prime is 10011134449. The reversal of 10011134431 is 13443111001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10011134431 - 23 = 10011134423 is a prime.

It is a super-2 number, since 2×100111344312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10011134399 and 10011134408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10011134401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310546 + ... + 341263.

It is an arithmetic number, because the mean of its divisors is an integer number (2502950400).

Almost surely, 210011134431 is an apocalyptic number.

10011134431 is a deficient number, since it is larger than the sum of its proper divisors (667169).

10011134431 is an equidigital number, since it uses as much as digits as its factorization.

10011134431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 667168.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10011134431 its reverse (13443111001), we get a palindrome (23454245432).

The spelling of 10011134431 in words is "ten billion, eleven million, one hundred thirty-four thousand, four hundred thirty-one".

Divisors: 1 15359 651809 10011134431