Base | Representation |
---|---|
bin | 11101001000101110110… |
… | …11101001100100110011 |
3 | 10112201001210211221011110 |
4 | 32210113123221210303 |
5 | 112400243322112430 |
6 | 2043524114444403 |
7 | 132220461610614 |
oct | 16442733514463 |
9 | 3481053757143 |
10 | 1001120504115 |
11 | 356633475256 |
12 | 142035293703 |
13 | 73536478224 |
14 | 366511a1c0b |
15 | 1b094cec7b0 |
hex | e9176e9933 |
1001120504115 has 64 divisors (see below), whose sum is σ = 1619604564480. Its totient is φ = 528028892160.
The previous prime is 1001120504047. The next prime is 1001120504117. The reversal of 1001120504115 is 5114050211001.
It is not a de Polignac number, because 1001120504115 - 210 = 1001120503091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1001120504091 and 1001120504100.
It is not an unprimeable number, because it can be changed into a prime (1001120504117) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1063889545 + ... + 1063890485.
It is an arithmetic number, because the mean of its divisors is an integer number (25306321320).
Almost surely, 21001120504115 is an apocalyptic number.
1001120504115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1001120504115 is a deficient number, since it is larger than the sum of its proper divisors (618484060365).
1001120504115 is a wasteful number, since it uses less digits than its factorization.
1001120504115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2532.
The product of its (nonzero) digits is 200, while the sum is 21.
Adding to 1001120504115 its reverse (5114050211001), we get a palindrome (6115170715116).
The spelling of 1001120504115 in words is "one trillion, one billion, one hundred twenty million, five hundred four thousand, one hundred fifteen".
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