Base | Representation |
---|---|
bin | 11101001000101110111… |
… | …01100010101010010011 |
3 | 10112201001211210010111122 |
4 | 32210113131202222103 |
5 | 112400243434000313 |
6 | 2043524133232455 |
7 | 132220466044601 |
oct | 16442735425223 |
9 | 3481054703448 |
10 | 1001121000083 |
11 | 356633783946 |
12 | 14203549272b |
13 | 735365bcbb9 |
14 | 36651290871 |
15 | 1b094d99708 |
hex | e917762a93 |
1001121000083 has 2 divisors, whose sum is σ = 1001121000084. Its totient is φ = 1001121000082.
The previous prime is 1001121000073. The next prime is 1001121000133. The reversal of 1001121000083 is 3800001211001.
It is a weak prime.
It is an emirp because it is prime and its reverse (3800001211001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1001121000083 - 210 = 1001120999059 is a prime.
It is not a weakly prime, because it can be changed into another prime (1001121000043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500560500041 + 500560500042.
It is an arithmetic number, because the mean of its divisors is an integer number (500560500042).
Almost surely, 21001121000083 is an apocalyptic number.
1001121000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001121000083 is an equidigital number, since it uses as much as digits as its factorization.
1001121000083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1001121000083 its reverse (3800001211001), we get a palindrome (4801122211084).
The spelling of 1001121000083 in words is "one trillion, one billion, one hundred twenty-one million, eighty-three", and thus it is an aban number.
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