10011212004113 has 4 divisors (see below), whose sum is σ = 10011317322048. Its totient is φ = 10011106686180.

The previous prime is 10011212004109. The next prime is 10011212004119. The reversal of 10011212004113 is 31140021211001.

10011212004113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10011212004113 - 2² = 10011212004109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10011212004091 and 10011212004100.

It is not an unprimeable number, because it can be changed into a prime (10011212004119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52516253 + ... + 52706538.

It is an arithmetic number, because the mean of its divisors is an integer number (2502829330512).

Almost surely, 2^{10011212004113} is an apocalyptic number.

It is an amenable number.

10011212004113 is a deficient number, since it is larger than the sum of its proper divisors (105317935).

10011212004113 is an equidigital number, since it uses as much as digits as its factorization.

10011212004113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105317934.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10011212004113 its reverse (31140021211001), we get a palindrome (41151233215114).

The spelling of 10011212004113 in words is "ten trillion, eleven billion, two hundred twelve million, four thousand, one hundred thirteen".