Base | Representation |
---|---|
bin | 1001000110101110101101… |
… | …0001110111101110011111 |
3 | 1022110001201012202201121002 |
4 | 2101223223101313232133 |
5 | 2303010440102131033 |
6 | 33143031432500515 |
7 | 2052200251361402 |
oct | 221535321675637 |
9 | 38401635681532 |
10 | 10011221130143 |
11 | 320a80a3771a2 |
12 | 11582a984a73b |
13 | 578091b27abc |
14 | 26878d521d39 |
15 | 1256351123e8 |
hex | 91aeb477b9f |
10011221130143 has 2 divisors, whose sum is σ = 10011221130144. Its totient is φ = 10011221130142.
The previous prime is 10011221130103. The next prime is 10011221130173. The reversal of 10011221130143 is 34103112211001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10011221130143 - 212 = 10011221126047 is a prime.
It is a super-2 number, since 2×100112211301432 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10011221130103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005610565071 + 5005610565072.
It is an arithmetic number, because the mean of its divisors is an integer number (5005610565072).
Almost surely, 210011221130143 is an apocalyptic number.
10011221130143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011221130143 is an equidigital number, since it uses as much as digits as its factorization.
10011221130143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 10011221130143 its reverse (34103112211001), we get a palindrome (44114333341144).
The spelling of 10011221130143 in words is "ten trillion, eleven billion, two hundred twenty-one million, one hundred thirty thousand, one hundred forty-three".
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