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10011221130143 is a prime number
BaseRepresentation
bin1001000110101110101101…
…0001110111101110011111
31022110001201012202201121002
42101223223101313232133
52303010440102131033
633143031432500515
72052200251361402
oct221535321675637
938401635681532
1010011221130143
11320a80a3771a2
1211582a984a73b
13578091b27abc
1426878d521d39
151256351123e8
hex91aeb477b9f

10011221130143 has 2 divisors, whose sum is σ = 10011221130144. Its totient is φ = 10011221130142.

The previous prime is 10011221130103. The next prime is 10011221130173. The reversal of 10011221130143 is 34103112211001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10011221130143 - 212 = 10011221126047 is a prime.

It is a super-2 number, since 2×100112211301432 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011221130103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005610565071 + 5005610565072.

It is an arithmetic number, because the mean of its divisors is an integer number (5005610565072).

Almost surely, 210011221130143 is an apocalyptic number.

10011221130143 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011221130143 is an equidigital number, since it uses as much as digits as its factorization.

10011221130143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 10011221130143 its reverse (34103112211001), we get a palindrome (44114333341144).

The spelling of 10011221130143 in words is "ten trillion, eleven billion, two hundred twenty-one million, one hundred thirty thousand, one hundred forty-three".