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100112220113 is a prime number
BaseRepresentation
bin101110100111100100…
…1110011111111010001
3100120101222210201022012
41131033021303333101
53120012212020423
6113554012152305
710142605554563
oct1351711637721
9316358721265
10100112220113
11395038137a4
121749b468695
139595b41489
144bb9d13333
15290e005078
hex174f273fd1

100112220113 has 2 divisors, whose sum is σ = 100112220114. Its totient is φ = 100112220112.

The previous prime is 100112220097. The next prime is 100112220137. The reversal of 100112220113 is 311022211001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90693129409 + 9419090704 = 301153^2 + 97052^2 .

It is an emirp because it is prime and its reverse (311022211001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100112220113 - 24 = 100112220097 is a prime.

It is not a weakly prime, because it can be changed into another prime (100112220713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056110056 + 50056110057.

It is an arithmetic number, because the mean of its divisors is an integer number (50056110057).

Almost surely, 2100112220113 is an apocalyptic number.

It is an amenable number.

100112220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100112220113 is an equidigital number, since it uses as much as digits as its factorization.

100112220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 100112220113 its reverse (311022211001), we get a palindrome (411134431114).

The spelling of 100112220113 in words is "one hundred billion, one hundred twelve million, two hundred twenty thousand, one hundred thirteen".