10011231104131 has 2 divisors, whose sum is σ = 10011231104132. Its totient is φ = 10011231104130.

The previous prime is 10011231104101. The next prime is 10011231104137. The reversal of 10011231104131 is 13140113211001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10011231104131 - 2²⁵ = 10011197549699 is a prime.

It is a super-2 number, since 2×10011231104131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10011231104099 and 10011231104108.

It is not a weakly prime, because it can be changed into another prime (10011231104137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005615552065 + 5005615552066.

It is an arithmetic number, because the mean of its divisors is an integer number (5005615552066).

Almost surely, 2^{10011231104131} is an apocalyptic number.

10011231104131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011231104131 is an equidigital number, since it uses as much as digits as its factorization.

10011231104131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 10011231104131 its reverse (13140113211001), we get a palindrome (23151344315132).

The spelling of 10011231104131 in words is "ten trillion, eleven billion, two hundred thirty-one million, one hundred four thousand, one hundred thirty-one".