10011231330001 has 4 divisors (see below), whose sum is σ = 10921343269104. Its totient is φ = 9101119390900.

The previous prime is 10011231329987. The next prime is 10011231330007. The reversal of 10011231330001 is 10003313211001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10011231330001 - 2¹⁵ = 10011231297233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10011231330007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455055969535 + ... + 455055969556.

It is an arithmetic number, because the mean of its divisors is an integer number (2730335817276).

Almost surely, 2^{10011231330001} is an apocalyptic number.

10011231330001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

10011231330001 is a deficient number, since it is larger than the sum of its proper divisors (910111939103).

10011231330001 is an equidigital number, since it uses as much as digits as its factorization.

10011231330001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 910111939102.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10011231330001 its reverse (10003313211001), we get a palindrome (20014544541002).

The spelling of 10011231330001 in words is "ten trillion, eleven billion, two hundred thirty-one million, three hundred thirty thousand, one".