100113100333 has 4 divisors (see below), whose sum is σ = 100144516480. Its totient is φ = 100081684188.

The previous prime is 100113100289. The next prime is 100113100363. The reversal of 100113100333 is 333001311001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 333001311001 = 89057 ⋅3739193.

It is a cyclic number.

It is not a de Polignac number, because 100113100333 - 2¹⁷ = 100112969261 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100113100363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15703293 + ... + 15709666.

It is an arithmetic number, because the mean of its divisors is an integer number (25036129120).

Almost surely, 2^100113100333 is an apocalyptic number.

It is an amenable number.

100113100333 is a deficient number, since it is larger than the sum of its proper divisors (31416147).

100113100333 is an equidigital number, since it uses as much as digits as its factorization.

100113100333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31416146.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 100113100333 its reverse (333001311001), we get a palindrome (433114411334).

The spelling of 100113100333 in words is "one hundred billion, one hundred thirteen million, one hundred thousand, three hundred thirty-three".