100113122003 has 2 divisors, whose sum is σ = 100113122004. Its totient is φ = 100113122002.

The previous prime is 100113121987. The next prime is 100113122017. The reversal of 100113122003 is 300221311001.

It is an a-pointer prime, because the next prime (100113122017) can be obtained adding 100113122003 to its sum of digits (14).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100113122003 - 2⁴ = 100113121987 is a prime.

It is a super-3 number, since 3×100113122003³ (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (100113122033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056561001 + 50056561002.

It is an arithmetic number, because the mean of its divisors is an integer number (50056561002).

Almost surely, 2^100113122003 is an apocalyptic number.

100113122003 is a deficient number, since it is larger than the sum of its proper divisors (1).

100113122003 is an equidigital number, since it uses as much as digits as its factorization.

100113122003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 100113122003 its reverse (300221311001), we get a palindrome (400334433004).

The spelling of 100113122003 in words is "one hundred billion, one hundred thirteen million, one hundred twenty-two thousand, three".