10011319993 has 2 divisors, whose sum is σ = 10011319994. Its totient is φ = 10011319992.

The previous prime is 10011319961. The next prime is 10011320021. The reversal of 10011319993 is 39991311001.

10011319993 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6075890704 + 3935429289 = 77948^2 + 62733^2 .

It is an emirp because it is prime and its reverse (39991311001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10011319993 - 2⁵ = 10011319961 is a prime.

It is not a weakly prime, because it can be changed into another prime (10011319693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005659996 + 5005659997.

It is an arithmetic number, because the mean of its divisors is an integer number (5005659997).

Almost surely, 2^10011319993 is an apocalyptic number.

It is an amenable number.

10011319993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011319993 is an equidigital number, since it uses as much as digits as its factorization.

10011319993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6561, while the sum is 37.

The spelling of 10011319993 in words is "ten billion, eleven million, three hundred nineteen thousand, nine hundred ninety-three".