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10011330132 = 2233461241051
BaseRepresentation
bin10010101001011100…
…01100011001010100
3221211201002021010220
421110232030121110
5131000400031012
64333225314340
7503042621256
oct112456143124
927751067126
1010011330132
114278153561
121b349359b0
13c371565ab
146ad871cd6
153d8d9a08c
hex254b8c654

10011330132 has 24 divisors (see below), whose sum is σ = 23366616672. Its totient is φ = 3336132000.

The previous prime is 10011330097. The next prime is 10011330139. The reversal of 10011330132 is 23103311001.

It is a super-2 number, since 2×100113301322 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10011330139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78994 + ... + 162057.

It is an arithmetic number, because the mean of its divisors is an integer number (973609028).

Almost surely, 210011330132 is an apocalyptic number.

10011330132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

10011330132 is an abundant number, since it is smaller than the sum of its proper divisors (13355286540).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10011330132 is a wasteful number, since it uses less digits than its factorization.

10011330132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 244519 (or 244517 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10011330132 its reverse (23103311001), we get a palindrome (33114641133).

The spelling of 10011330132 in words is "ten billion, eleven million, three hundred thirty thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 3461 6922 10383 13844 20766 41532 241051 482102 723153 964204 1446306 2892612 834277511 1668555022 2502832533 3337110044 5005665066 10011330132