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100118973528463 is a prime number
BaseRepresentation
bin10110110000111011000011…
…110110100011100110001111
3111010111021120101222222112211
4112300323003312203212033
5101110322124210402323
6552534004350211251
730042233332352251
oct2660730366434617
9433437511888484
10100118973528463
11299a024450800a
12b28b8897b3b27
1343b32427851b6
141aa1ad9ab9cd1
15b894ce5b570d
hex5b0ec3da398f

100118973528463 has 2 divisors, whose sum is σ = 100118973528464. Its totient is φ = 100118973528462.

The previous prime is 100118973528407. The next prime is 100118973528479. The reversal of 100118973528463 is 364825379811001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100118973528463 is a prime.

It is a super-2 number, since 2×1001189735284632 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100118973528398 and 100118973528407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100118970528463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50059486764231 + 50059486764232.

It is an arithmetic number, because the mean of its divisors is an integer number (50059486764232).

It is a 1-persistent number, because it is pandigital, but 2⋅100118973528463 = 200237947056926 is not.

Almost surely, 2100118973528463 is an apocalyptic number.

100118973528463 is a deficient number, since it is larger than the sum of its proper divisors (1).

100118973528463 is an equidigital number, since it uses as much as digits as its factorization.

100118973528463 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8709120, while the sum is 58.

The spelling of 100118973528463 in words is "one hundred trillion, one hundred eighteen billion, nine hundred seventy-three million, five hundred twenty-eight thousand, four hundred sixty-three".