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1001202344143 is a prime number
BaseRepresentation
bin11101001000111000100…
…11110110000011001111
310112201021111211211120121
432210130103312003033
5112400430300003033
62043540200525411
7132222504336361
oct16443423660317
93481244754517
101001202344143
11356675692941
12142058780867
137354a400c91
143665bdc6d31
151b09c0b662d
hexe91c4f60cf

1001202344143 has 2 divisors, whose sum is σ = 1001202344144. Its totient is φ = 1001202344142.

The previous prime is 1001202344119. The next prime is 1001202344173. The reversal of 1001202344143 is 3414432021001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1001202344143 is a prime.

It is a super-3 number, since 3×10012023441433 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001202344113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500601172071 + 500601172072.

It is an arithmetic number, because the mean of its divisors is an integer number (500601172072).

Almost surely, 21001202344143 is an apocalyptic number.

1001202344143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001202344143 is an equidigital number, since it uses as much as digits as its factorization.

1001202344143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1001202344143 its reverse (3414432021001), we get a palindrome (4415634365144).

The spelling of 1001202344143 in words is "one trillion, one billion, two hundred two million, three hundred forty-four thousand, one hundred forty-three".