Base | Representation |
---|---|
bin | 11101001000111001100… |
… | …01000011001010110011 |
3 | 10112201022001020210111202 |
4 | 32210130301003022303 |
5 | 112400434230000201 |
6 | 2043541033001415 |
7 | 132222626403662 |
oct | 16443461031263 |
9 | 3481261223452 |
10 | 1001210000051 |
11 | 356679a41938 |
12 | 14205b25326b |
13 | 7354bb818c1 |
14 | 3665d01add9 |
15 | 1b09cac9c6b |
hex | e91cc432b3 |
1001210000051 has 2 divisors, whose sum is σ = 1001210000052. Its totient is φ = 1001210000050.
The previous prime is 1001210000023. The next prime is 1001210000057. The reversal of 1001210000051 is 1500000121001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1001210000051 - 218 = 1001209737907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1001209999987 and 1001210000041.
It is not a weakly prime, because it can be changed into another prime (1001210000057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500605000025 + 500605000026.
It is an arithmetic number, because the mean of its divisors is an integer number (500605000026).
Almost surely, 21001210000051 is an apocalyptic number.
1001210000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001210000051 is an equidigital number, since it uses as much as digits as its factorization.
1001210000051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10, while the sum is 11.
Adding to 1001210000051 its reverse (1500000121001), we get a palindrome (2501210121052).
The spelling of 1001210000051 in words is "one trillion, one billion, two hundred ten million, fifty-one", and thus it is an aban number.
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