Base | Representation |
---|---|
bin | 10110110000111100111101… |
… | …001111100010110100001101 |
3 | 111010111110211100012122122222 |
4 | 112300330331033202310031 |
5 | 101110340312042400442 |
6 | 552534542421345125 |
7 | 30042334652203604 |
oct | 2660747517426415 |
9 | 433443740178588 |
10 | 100121010121997 |
11 | 299a109a078967 |
12 | b2901578681a5 |
13 | 43b34a86a2727 |
14 | 1aa1c5037ca3b |
15 | b8959d2a58d2 |
hex | 5b0f3d3e2d0d |
100121010121997 has 2 divisors, whose sum is σ = 100121010121998. Its totient is φ = 100121010121996.
The previous prime is 100121010121981. The next prime is 100121010122113. The reversal of 100121010121997 is 799121010121001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60365223484036 + 39755786637961 = 7769506^2 + 6305219^2 .
It is a cyclic number.
It is not a de Polignac number, because 100121010121997 - 24 = 100121010121981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100121010121697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060505060998 + 50060505060999.
It is an arithmetic number, because the mean of its divisors is an integer number (50060505060999).
Almost surely, 2100121010121997 is an apocalyptic number.
It is an amenable number.
100121010121997 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121010121997 is an equidigital number, since it uses as much as digits as its factorization.
100121010121997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 35.
Adding to 100121010121997 its reverse (799121010121001), we get a palindrome (899242020242998).
The spelling of 100121010121997 in words is "one hundred trillion, one hundred twenty-one billion, ten million, one hundred twenty-one thousand, nine hundred ninety-seven".
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