Base | Representation |
---|---|
bin | 11101001000111001100… |
… | …01100000011100111111 |
3 | 10112201022001110220001021 |
4 | 32210130301200130333 |
5 | 112400434242314444 |
6 | 2043541035325011 |
7 | 132222630413455 |
oct | 16443461403477 |
9 | 3481261426037 |
10 | 1001210119999 |
11 | 35667a013a71 |
12 | 14205b2b0767 |
13 | 7354bbc438b |
14 | 3665d04c9d5 |
15 | 1b09cb00584 |
hex | e91cc6073f |
1001210119999 has 2 divisors, whose sum is σ = 1001210120000. Its totient is φ = 1001210119998.
The previous prime is 1001210119957. The next prime is 1001210120003. The reversal of 1001210119999 is 9999110121001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1001210119999 - 213 = 1001210111807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001210119699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500605059999 + 500605060000.
It is an arithmetic number, because the mean of its divisors is an integer number (500605060000).
Almost surely, 21001210119999 is an apocalyptic number.
1001210119999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001210119999 is an equidigital number, since it uses as much as digits as its factorization.
1001210119999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13122, while the sum is 43.
The spelling of 1001210119999 in words is "one trillion, one billion, two hundred ten million, one hundred nineteen thousand, nine hundred ninety-nine".
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