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10012101212143 is a prime number
BaseRepresentation
bin1001000110110001111110…
…1111000111011111101111
31022110010222112210112010201
42101230133233013133233
52303014240402242033
633143255032014331
72052231126062212
oct221543757073757
938403875715121
1010012101212143
113210121134898
1211584b45313a7
135781a2269494
14268834375779
1512568750747d
hex91b1fbc77ef

10012101212143 has 2 divisors, whose sum is σ = 10012101212144. Its totient is φ = 10012101212142.

The previous prime is 10012101212063. The next prime is 10012101212147. The reversal of 10012101212143 is 34121210121001.

It is a strong prime.

It is an emirp because it is prime and its reverse (34121210121001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10012101212143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10012101212143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012101212147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006050606071 + 5006050606072.

It is an arithmetic number, because the mean of its divisors is an integer number (5006050606072).

Almost surely, 210012101212143 is an apocalyptic number.

10012101212143 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012101212143 is an equidigital number, since it uses as much as digits as its factorization.

10012101212143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 10012101212143 its reverse (34121210121001), we get a palindrome (44133311333144).

The spelling of 10012101212143 in words is "ten trillion, twelve billion, one hundred one million, two hundred twelve thousand, one hundred forty-three".