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10012103113333 is a prime number
BaseRepresentation
bin1001000110110001111111…
…0110010111101001110101
31022110010222200101010002011
42101230133312113221311
52303014241344111313
633143255140444221
72052231151201066
oct221543766275165
938403880333064
1010012103113333
113210122213222
1211584b50a9671
135781a2783949
1426883470c56d
1512568778093d
hex91b1fd97a75

10012103113333 has 2 divisors, whose sum is σ = 10012103113334. Its totient is φ = 10012103113332.

The previous prime is 10012103113321. The next prime is 10012103113343. The reversal of 10012103113333 is 33331130121001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9940917138084 + 71185975249 = 3152922^2 + 266807^2 .

It is an emirp because it is prime and its reverse (33331130121001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10012103113333 - 233 = 10003513178741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012103113343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006051556666 + 5006051556667.

It is an arithmetic number, because the mean of its divisors is an integer number (5006051556667).

Almost surely, 210012103113333 is an apocalyptic number.

It is an amenable number.

10012103113333 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012103113333 is an equidigital number, since it uses as much as digits as its factorization.

10012103113333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 10012103113333 its reverse (33331130121001), we get a palindrome (43343233234334).

The spelling of 10012103113333 in words is "ten trillion, twelve billion, one hundred three million, one hundred thirteen thousand, three hundred thirty-three".