Base | Representation |
---|---|
bin | 10110110000111101001000… |
… | …110000100011100010111111 |
3 | 111010111111022210202101112011 |
4 | 112300331020300203202333 |
5 | 101110341211022400434 |
6 | 552535013522352051 |
7 | 30042342516332164 |
oct | 2660751060434277 |
9 | 433444283671464 |
10 | 100121203325119 |
11 | 299a1189139269 |
12 | b2901b04bb627 |
13 | 43b350971a0c2 |
14 | 1aa1c6bcb206b |
15 | b895b021ae64 |
hex | 5b0f48c238bf |
100121203325119 has 2 divisors, whose sum is σ = 100121203325120. Its totient is φ = 100121203325118.
The previous prime is 100121203325107. The next prime is 100121203325167. The reversal of 100121203325119 is 911523302121001.
It is a weak prime.
It is an emirp because it is prime and its reverse (911523302121001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100121203325119 - 29 = 100121203324607 is a prime.
It is a super-2 number, since 2×1001212033251192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100121203325189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060601662559 + 50060601662560.
It is an arithmetic number, because the mean of its divisors is an integer number (50060601662560).
Almost surely, 2100121203325119 is an apocalyptic number.
100121203325119 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121203325119 is an equidigital number, since it uses as much as digits as its factorization.
100121203325119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 31.
The spelling of 100121203325119 in words is "one hundred trillion, one hundred twenty-one billion, two hundred three million, three hundred twenty-five thousand, one hundred nineteen".
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