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10012121210023 is a prime number
BaseRepresentation
bin1001000110110010000011…
…1011011001110010100111
31022110011000221102112001221
42101230200323121302213
52303014311012210043
633143301024401211
72052231461052112
oct221544073316247
938404027375057
1010012121210023
113210131453569
1211584bb176207
135781a644b94a
14268836c9d579
151256891578ed
hex91b20ed9ca7

10012121210023 has 2 divisors, whose sum is σ = 10012121210024. Its totient is φ = 10012121210022.

The previous prime is 10012121209933. The next prime is 10012121210057. The reversal of 10012121210023 is 32001212121001.

10012121210023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10012121210023 - 217 = 10012121078951 is a prime.

It is a super-2 number, since 2×100121212100232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10012121209979 and 10012121210006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012121210083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006060605011 + 5006060605012.

It is an arithmetic number, because the mean of its divisors is an integer number (5006060605012).

Almost surely, 210012121210023 is an apocalyptic number.

10012121210023 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012121210023 is an equidigital number, since it uses as much as digits as its factorization.

10012121210023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10012121210023 its reverse (32001212121001), we get a palindrome (42013333331024).

The spelling of 10012121210023 in words is "ten trillion, twelve billion, one hundred twenty-one million, two hundred ten thousand, twenty-three".