Base | Representation |
---|---|
bin | 11101001000111001110… |
… | …01011111001110000001 |
3 | 10112201022012102011212101 |
4 | 32210130321133032001 |
5 | 112400440311241342 |
6 | 2043541152230401 |
7 | 132222654246046 |
oct | 16443471371601 |
9 | 3481265364771 |
10 | 1001212212097 |
11 | 356680212879 |
12 | 14205bb3b401 |
13 | 7354c4776c6 |
14 | 3665d4351cd |
15 | 1b09cdb53b7 |
hex | e91ce5f381 |
1001212212097 has 2 divisors, whose sum is σ = 1001212212098. Its totient is φ = 1001212212096.
The previous prime is 1001212212083. The next prime is 1001212212167. The reversal of 1001212212097 is 7902122121001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 903724014736 + 97488197361 = 950644^2 + 312231^2 .
It is a cyclic number.
It is not a de Polignac number, because 1001212212097 - 215 = 1001212179329 is a prime.
It is a super-2 number, since 2×10012122120972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1001212212197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500606106048 + 500606106049.
It is an arithmetic number, because the mean of its divisors is an integer number (500606106049).
Almost surely, 21001212212097 is an apocalyptic number.
It is an amenable number.
1001212212097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001212212097 is an equidigital number, since it uses as much as digits as its factorization.
1001212212097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 28.
Adding to 1001212212097 its reverse (7902122121001), we get a palindrome (8903334333098).
The spelling of 1001212212097 in words is "one trillion, one billion, two hundred twelve million, two hundred twelve thousand, ninety-seven".
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