Base | Representation |
---|---|
bin | 11101001000111001110… |
… | …01011111001111100101 |
3 | 10112201022012102012000002 |
4 | 32210130321133033211 |
5 | 112400440311242242 |
6 | 2043541152231045 |
7 | 132222654246251 |
oct | 16443471371745 |
9 | 3481265365002 |
10 | 1001212212197 |
11 | 35668021295a |
12 | 14205bb3b485 |
13 | 7354c477772 |
14 | 3665d435261 |
15 | 1b09cdb5432 |
hex | e91ce5f3e5 |
1001212212197 has 2 divisors, whose sum is σ = 1001212212198. Its totient is φ = 1001212212196.
The previous prime is 1001212212167. The next prime is 1001212212211. The reversal of 1001212212197 is 7912122121001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 851474944516 + 149737267681 = 922754^2 + 386959^2 .
It is a cyclic number.
It is not a de Polignac number, because 1001212212197 - 228 = 1000943776741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001212212167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500606106098 + 500606106099.
It is an arithmetic number, because the mean of its divisors is an integer number (500606106099).
Almost surely, 21001212212197 is an apocalyptic number.
It is an amenable number.
1001212212197 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001212212197 is an equidigital number, since it uses as much as digits as its factorization.
1001212212197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 29.
Adding to 1001212212197 its reverse (7912122121001), we get a palindrome (8913334333198).
The spelling of 1001212212197 in words is "one trillion, one billion, two hundred twelve million, two hundred twelve thousand, one hundred ninety-seven".
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