Base | Representation |
---|---|
bin | 101110100111110110… |
… | …0011111011111100111 |
3 | 100120102121220120221101 |
4 | 1131033230133133213 |
5 | 3120022023424312 |
6 | 113554535100531 |
7 | 10143046050331 |
oct | 1351754373747 |
9 | 316377816841 |
10 | 100121311207 |
11 | 39508962aa5 |
12 | 174a2511747 |
13 | 95979a5418 |
14 | 4bbb1dc451 |
15 | 290ebeda57 |
hex | 174fb1f7e7 |
100121311207 has 2 divisors, whose sum is σ = 100121311208. Its totient is φ = 100121311206.
The previous prime is 100121311183. The next prime is 100121311253. The reversal of 100121311207 is 702113121001.
It is a weak prime.
It is an emirp because it is prime and its reverse (702113121001) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100121311207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100121311907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060655603 + 50060655604.
It is an arithmetic number, because the mean of its divisors is an integer number (50060655604).
Almost surely, 2100121311207 is an apocalyptic number.
100121311207 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121311207 is an equidigital number, since it uses as much as digits as its factorization.
100121311207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 100121311207 its reverse (702113121001), we get a palindrome (802234432208).
The spelling of 100121311207 in words is "one hundred billion, one hundred twenty-one million, three hundred eleven thousand, two hundred seven".
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