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1001213232013 = 6251711601503
BaseRepresentation
bin11101001000111001111…
…01011000001110001101
310112201022021022222221001
432210130331120032031
5112400441041411023
62043541230140301
7132222666024421
oct16443475301615
93481267288831
101001213232013
1135668084a085
12142060351691
137354c7439c7
143665d61cb81
151b09d0176ad
hexe91cf5838d

1001213232013 has 4 divisors (see below), whose sum is σ = 1001215458688. Its totient is φ = 1001211005340.

The previous prime is 1001213231987. The next prime is 1001213232029. The reversal of 1001213232013 is 3102323121001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1001213232013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1001213232113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175581 + ... + 1425922.

It is an arithmetic number, because the mean of its divisors is an integer number (250303864672).

Almost surely, 21001213232013 is an apocalyptic number.

It is an amenable number.

1001213232013 is a deficient number, since it is larger than the sum of its proper divisors (2226675).

1001213232013 is an equidigital number, since it uses as much as digits as its factorization.

1001213232013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2226674.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1001213232013 its reverse (3102323121001), we get a palindrome (4103536353014).

The spelling of 1001213232013 in words is "one trillion, one billion, two hundred thirteen million, two hundred thirty-two thousand, thirteen".

Divisors: 1 625171 1601503 1001213232013