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100121340104413 is a prime number
BaseRepresentation
bin10110110000111101010000…
…111010010100111011011101
3111010111111200100010111102221
4112300331100322110323131
5101110342001031320123
6552535035250145341
730042346100046505
oct2660752072247335
9433444610114387
10100121340104413
11299a1249370601
12b29022a282251
1343b352bb6a4b4
141aa1c82118a05
15b895bc23825d
hex5b0f50e94edd

100121340104413 has 2 divisors, whose sum is σ = 100121340104414. Its totient is φ = 100121340104412.

The previous prime is 100121340104381. The next prime is 100121340104453. The reversal of 100121340104413 is 314401043121001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69407110574649 + 30714229529764 = 8331093^2 + 5542042^2 .

It is a cyclic number.

It is not a de Polignac number, because 100121340104413 - 25 = 100121340104381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100121340104453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060670052206 + 50060670052207.

It is an arithmetic number, because the mean of its divisors is an integer number (50060670052207).

Almost surely, 2100121340104413 is an apocalyptic number.

It is an amenable number.

100121340104413 is a deficient number, since it is larger than the sum of its proper divisors (1).

100121340104413 is an equidigital number, since it uses as much as digits as its factorization.

100121340104413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 100121340104413 its reverse (314401043121001), we get a palindrome (414522383225414).

The spelling of 100121340104413 in words is "one hundred trillion, one hundred twenty-one billion, three hundred forty million, one hundred four thousand, four hundred thirteen".