Base | Representation |
---|---|
bin | 10110110000111101111000… |
… | …001000000001011010011101 |
3 | 111010111120101012002100122022 |
4 | 112300331320020001122131 |
5 | 101110344322442142132 |
6 | 552535224431225525 |
7 | 30042401306112626 |
oct | 2660757010013235 |
9 | 433446335070568 |
10 | 100121998005917 |
11 | 299a1556776758 |
12 | b2903926782a5 |
13 | 43b3605259b24 |
14 | 1aa1d05654a4d |
15 | b89609d91e12 |
hex | 5b0f7820169d |
100121998005917 has 2 divisors, whose sum is σ = 100121998005918. Its totient is φ = 100121998005916.
The previous prime is 100121998005877. The next prime is 100121998005943. The reversal of 100121998005917 is 719500899121001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72504986580196 + 27617011425721 = 8514986^2 + 5255189^2 .
It is a cyclic number.
It is not a de Polignac number, because 100121998005917 - 222 = 100121993811613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100121998065917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060999002958 + 50060999002959.
It is an arithmetic number, because the mean of its divisors is an integer number (50060999002959).
Almost surely, 2100121998005917 is an apocalyptic number.
It is an amenable number.
100121998005917 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121998005917 is an equidigital number, since it uses as much as digits as its factorization.
100121998005917 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 408240, while the sum is 53.
The spelling of 100121998005917 in words is "one hundred trillion, one hundred twenty-one billion, nine hundred ninety-eight million, five thousand, nine hundred seventeen".
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