Base | Representation |
---|---|
bin | 10110110000111101111000… |
… | …111001100101110011011011 |
3 | 111010111120102002112112012122 |
4 | 112300331320321211303123 |
5 | 101110344334304000102 |
6 | 552535230013531455 |
7 | 30042401524422422 |
oct | 2660757071456333 |
9 | 433446362475178 |
10 | 100122011000027 |
11 | 299a1563041395 |
12 | b290396aa3b8b |
13 | 43b3607b59453 |
14 | 1aa1d072782b9 |
15 | b8960b0ac0a2 |
hex | 5b0f78e65cdb |
100122011000027 has 2 divisors, whose sum is σ = 100122011000028. Its totient is φ = 100122011000026.
The previous prime is 100122010999979. The next prime is 100122011000041. The reversal of 100122011000027 is 720000110221001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100122011000027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100122010999969 and 100122011000014.
It is not a weakly prime, because it can be changed into another prime (100122011020027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061005500013 + 50061005500014.
It is an arithmetic number, because the mean of its divisors is an integer number (50061005500014).
Almost surely, 2100122011000027 is an apocalyptic number.
100122011000027 is a deficient number, since it is larger than the sum of its proper divisors (1).
100122011000027 is an equidigital number, since it uses as much as digits as its factorization.
100122011000027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 100122011000027 its reverse (720000110221001), we get a palindrome (820122121221028).
The spelling of 100122011000027 in words is "one hundred trillion, one hundred twenty-two billion, eleven million, twenty-seven", and thus it is an aban number.
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