Base | Representation |
---|---|
bin | 101110100111110111… |
… | …1001010100111100011 |
3 | 100120102200020012102112 |
4 | 1131033233022213203 |
5 | 3120022213342011 |
6 | 113555002105535 |
7 | 10143055030001 |
oct | 1351757124743 |
9 | 316380205375 |
10 | 100122012131 |
11 | 395092a1679 |
12 | 174a27ab2ab |
13 | 9597b8c47b |
14 | 4bbb341a71 |
15 | 290ecdb58b |
hex | 174fbca9e3 |
100122012131 has 2 divisors, whose sum is σ = 100122012132. Its totient is φ = 100122012130.
The previous prime is 100122012079. The next prime is 100122012187. The reversal of 100122012131 is 131210221001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100122012131 - 210 = 100122011107 is a prime.
It is a super-2 number, since 2×1001220121312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100122012031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061006065 + 50061006066.
It is an arithmetic number, because the mean of its divisors is an integer number (50061006066).
Almost surely, 2100122012131 is an apocalyptic number.
100122012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100122012131 is an equidigital number, since it uses as much as digits as its factorization.
100122012131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 100122012131 its reverse (131210221001), we get a palindrome (231332233132).
The spelling of 100122012131 in words is "one hundred billion, one hundred twenty-two million, twelve thousand, one hundred thirty-one".
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