Base | Representation |
---|---|
bin | 101110100111110111… |
… | …1001011110100000101 |
3 | 100120102200020110010221 |
4 | 1131033233023310011 |
5 | 3120022214021104 |
6 | 113555002144341 |
7 | 10143055050166 |
oct | 1351757136405 |
9 | 316380213127 |
10 | 100122017029 |
11 | 395092a5321 |
12 | 174a27b20b1 |
13 | 9597b91778 |
14 | 4bbb34376d |
15 | 290ecdcc54 |
hex | 174fbcbd05 |
100122017029 has 2 divisors, whose sum is σ = 100122017030. Its totient is φ = 100122017028.
The previous prime is 100122017011. The next prime is 100122017077. The reversal of 100122017029 is 920710221001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55726684225 + 44395332804 = 236065^2 + 210702^2 .
It is a cyclic number.
It is not a de Polignac number, because 100122017029 - 25 = 100122016997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100122016994 and 100122017012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100122057029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061008514 + 50061008515.
It is an arithmetic number, because the mean of its divisors is an integer number (50061008515).
Almost surely, 2100122017029 is an apocalyptic number.
It is an amenable number.
100122017029 is a deficient number, since it is larger than the sum of its proper divisors (1).
100122017029 is an equidigital number, since it uses as much as digits as its factorization.
100122017029 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
The spelling of 100122017029 in words is "one hundred billion, one hundred twenty-two million, seventeen thousand, twenty-nine".
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