Base | Representation |
---|---|
bin | 1001000110110010010110… |
… | …1111111110010111110011 |
3 | 1022110011020120122011112211 |
4 | 2101230211233332113303 |
5 | 2303014442214201321 |
6 | 33143313034232551 |
7 | 2052233462443423 |
oct | 221544557762763 |
9 | 38404216564484 |
10 | 10012202100211 |
11 | 3210173082563 |
12 | 1158522285757 |
13 | 5781ba13126c |
14 | 268843918483 |
15 | 1256912d50e1 |
hex | 91b25bfe5f3 |
10012202100211 has 2 divisors, whose sum is σ = 10012202100212. Its totient is φ = 10012202100210.
The previous prime is 10012202100203. The next prime is 10012202100259. The reversal of 10012202100211 is 11200120221001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10012202100211 - 23 = 10012202100203 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10012202100191 and 10012202100200.
It is not a weakly prime, because it can be changed into another prime (10012202100011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006101050105 + 5006101050106.
It is an arithmetic number, because the mean of its divisors is an integer number (5006101050106).
Almost surely, 210012202100211 is an apocalyptic number.
10012202100211 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012202100211 is an equidigital number, since it uses as much as digits as its factorization.
10012202100211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 10012202100211 its reverse (11200120221001), we get a palindrome (21212322321212).
The spelling of 10012202100211 in words is "ten trillion, twelve billion, two hundred two million, one hundred thousand, two hundred eleven".
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