Base | Representation |
---|---|
bin | 10110110000111101111001… |
… | …100011100011100101101011 |
3 | 111010111120102212020102201012 |
4 | 112300331321203203211223 |
5 | 101110344400113013003 |
6 | 552535231045414135 |
7 | 30042402020061302 |
oct | 2660757143434553 |
9 | 433446385212635 |
10 | 100122022001003 |
11 | 299a1569275602 |
12 | b29039a70a34b |
13 | 43b360a20b7c2 |
14 | 1aa1d088dd439 |
15 | b8960c0318d8 |
hex | 5b0f798e396b |
100122022001003 has 2 divisors, whose sum is σ = 100122022001004. Its totient is φ = 100122022001002.
The previous prime is 100122022000901. The next prime is 100122022001009. The reversal of 100122022001003 is 300100220221001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100122022001003 is a prime.
It is a super-2 number, since 2×1001220220010032 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (100122022001009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061011000501 + 50061011000502.
It is an arithmetic number, because the mean of its divisors is an integer number (50061011000502).
Almost surely, 2100122022001003 is an apocalyptic number.
100122022001003 is a deficient number, since it is larger than the sum of its proper divisors (1).
100122022001003 is an equidigital number, since it uses as much as digits as its factorization.
100122022001003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 100122022001003 its reverse (300100220221001), we get a palindrome (400222242222004).
The spelling of 100122022001003 in words is "one hundred trillion, one hundred twenty-two billion, twenty-two million, one thousand, three".
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