1001221003313 has 4 divisors (see below), whose sum is σ = 1002838485360. Its totient is φ = 999603521268.

The previous prime is 1001221003271. The next prime is 1001221003319. The reversal of 1001221003313 is 3133001221001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1001221003313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1001221003291 and 1001221003300.

It is not an unprimeable number, because it can be changed into a prime (1001221003319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808740095 + ... + 808741332.

It is an arithmetic number, because the mean of its divisors is an integer number (250709621340).

Almost surely, 2^{1001221003313} is an apocalyptic number.

It is an amenable number.

1001221003313 is a deficient number, since it is larger than the sum of its proper divisors (1617482047).

1001221003313 is an equidigital number, since it uses as much as digits as its factorization.

1001221003313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1617482046.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1001221003313 its reverse (3133001221001), we get a palindrome (4134222224314).

The spelling of 1001221003313 in words is "one trillion, one billion, two hundred twenty-one million, three thousand, three hundred thirteen".